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2=0.013x^2-1.18x+28.24
We move all terms to the left:
2-(0.013x^2-1.18x+28.24)=0
We get rid of parentheses
-0.013x^2+1.18x-28.24+2=0
We add all the numbers together, and all the variables
-0.013x^2+1.18x-26.24=0
a = -0.013; b = 1.18; c = -26.24;
Δ = b2-4ac
Δ = 1.182-4·(-0.013)·(-26.24)
Δ = 0.02792
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.18)-\sqrt{0.02792}}{2*-0.013}=\frac{-1.18-\sqrt{0.02792}}{-0.026} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.18)+\sqrt{0.02792}}{2*-0.013}=\frac{-1.18+\sqrt{0.02792}}{-0.026} $
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